a fort had provision for 50 men for 80 days. after 10 days, 50 more men arrived. how long will the remaining food last at the same rate?
Answers
Step-by-step explanation:
No. of men at the beginning =450
No. of men arrived after 10 days =50
Total Number of mens after 10 days =450+50=500
Total . of days =80
After 10 days, period =70 days
After 10 days, there will be 500 mens
Let x be the no. of days till which the food remains
∴450:500=70:x
By inverse proportion,
500:450=70:x
⟹
450
500
=
x
70
⟹x=
500
70×450
⟹x=63
Hence, till 63 days, the remaining food lasts at the same rate.
Step-by-step explanation:
The food lasts for 63 days
Step-by-step explanation:
Provision lasts for 450 men = 80 days
After 10 days , 50 more men arrived
Provision lasts for 450 men = 70 days
Provision lasts for 1 man = 70 \times 45070×450
Now number of men = 450+50 = 500
Provision lasts for 500 man = \frac{70 \times 450}{500}=6350070×450=63
Hence the food lasts for 63 days
#Learn more:
A fort had provisions for 150 men for 45 days. After 10 days 25 men left the fort .How long will the food last at the same rate?