A four times enlarged virtual image of an object ,placed at a distance of 15 cm from a lens ,is formed.Find the distance of image from the lens and focal lenght of the lens.
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Answer:
focal length =12cm&v=60cm
Explanation:m=v/u as v=m×u=-15×-4=60cm
1/v-1/u=1/f ,1/60-1/-15=1/60+1/15=1/60+1×4/15×4=1/60+4/60
=1/12,therefore,f=12cm
hope it helps uuu
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