A fraction becomes 1/3 if 1 is subtracted from both its numerator and denominator . If 1 is added to both numerator and denominator, it becomes 1/2. Find the fraction.
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Answered by
0
x-1/y-1=1/3.....1
x+1/y+1=1/2....2
from 1
3x-y=2...3
from 2
2x-y=-1....4
subtracting 3 from 4
2x-y+y-3x=-1-3
x=1
putting the value of x in 3
3-y=2
y=1
so the fraction is 1/1
x+1/y+1=1/2....2
from 1
3x-y=2...3
from 2
2x-y=-1....4
subtracting 3 from 4
2x-y+y-3x=-1-3
x=1
putting the value of x in 3
3-y=2
y=1
so the fraction is 1/1
Anonymous:
equation 3 and 4 can u please explain
answer is wrong as it does'nt satisfy the conditions given in the question
ok
Answered by
1
Let the fraction be p/q
(p-1)/(q-1) = 1/3
(p+1)/(q+1) = 1/2
3p - 3 = q -1 ⇒ 3p -2 = q
2p +2 = q +1 ⇒ 2p + 1 = q
3p -2 = 2p +1
p = 3 ⇒ p = 3
q= 6+1 = 7
So the fraction p/q is 3/7
(p-1)/(q-1) = 1/3
(p+1)/(q+1) = 1/2
3p - 3 = q -1 ⇒ 3p -2 = q
2p +2 = q +1 ⇒ 2p + 1 = q
3p -2 = 2p +1
p = 3 ⇒ p = 3
q= 6+1 = 7
So the fraction p/q is 3/7
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