Question

A fraction becomes 1/3 when 2 is subtracted from the numerator and
it becomes 1/2 when 1 is subtracted from the denominater. Find the fraction.
Class 10 Mathematics QUESTION
please solve step by step
please help me ​

Answer 1

Answer:

Answer in the attachment

Step-by-step explanation:

Hope it helps you

Answer 2

$Question</p><p></p><p>\sf{Solve= \dfrac{12x+17}{3x+1} -\dfrac{ 2x+15}{X+7}=3\dfrac{1}{5}}Solve=3x+112x+17−X+72x+15=351</p><p></p><p>\begin{gathered}\\\end{gathered}</p><p></p><p>\sf{Answer \bold{ = -68/9\ \ \ \ or\ \ 3}}Answer=−68/9    or  3</p><p></p><p>\begin{gathered}\\ \end{gathered}</p><p></p><p>Step by step explanation:</p><p></p><p>\begin{gathered} \\\end{gathered}</p><p></p><p>\sf{\Rightarrow\dfrac{12x+17}{3x+1} -\dfrac{ 2x+15}{X+7}=\dfrac{16}{5}}⇒3x+112x+17−X+72x+15=516</p><p></p><p>\sf{\Rightarrow\dfrac{12x+17}{3x+1} -\dfrac{ 2x+15}{x+7}=\dfrac{16}{5}}⇒3x+112x+17−x+72x+15=516</p><p></p><p>\sf{\Rightarrow \dfrac{12x+17}{3x+1} -\dfrac{ 2x+15}{X+7}=\dfrac{16}{5}}⇒3x+112x+17−X+72x+15=516</p><p></p><p>\sf{\Rightarrow \frac{((12x+17)(x+7) - (2x+15)(3x+1))}{((x+7)(3x+1))} = \frac{16}{ 5}}⇒((x+7)(3x+1))((12x+17)(x+7)−(2x+15)(3x+1))=516</p><p></p><p>\sf{\Rightarrow \frac{(12 {x}^{2} +101x+119-6 {x}^{2} -47x-15)}{(3 {x}^{2} +22x+7)} = \frac{16}{ 5}}⇒(3x2+22x+7)(12x2+101x+119−6x2−47x−15)=516</p><p></p><p>\sf{\Rightarrow\frac{(6{x}^{2} +54x+104 )}{(3 {x}^{2} +22x+7)} = \frac{16}{ 5} }⇒(3x2+22x+7)(6x2+54x+104)=516</p><p></p><p>\sf{\Rightarrow {5(6 {x}^{2} +54x+104)} = {16(3 {x}^{2} +22x+7)}}⇒5(6x2+54x+104)=16(3x2+22x+7)</p><p></p><p>\sf{\Rightarrow30 {x}^{2} +270x+520 = 48 {x}^{2} +352x+112}⇒30x2+270x+520=48x2+352x+112</p><p></p><p>\sf{\Rightarrow 18 {x}^{2} +82x-408 = 0}⇒18x2+82x−408=0</p><p></p><p>\sf{\Longrightarrow{9 {x}^{2} +41x-204 = 0}}⟹9x2+41x−204=0</p><p></p><p>\sf{\Rightarrow9 {x}^{2} - 27x + 68x - 204 = 0}⇒9x2−27x+68x−204=0</p><p></p><p>\sf{\Rightarrow 9x(x-3)+68(x-3) = 0}⇒9x(x−3)+68(x−3)=0</p><p></p><p>\sf{\Longrightarrow (9x+68)(x-3) = 0 }⟹(9x+68)(x−3)=0</p><p></p><p>\sf{\Longrightarrow x = \frac{ - 68}{9} \: \: or \: \: 3}⟹x=9−68or3</p><p></p><p>$