A fraction becomes 8/9 if 1 is added to both numerator and denominator,if however 5 is subtracted from numerator&denominator the fraction becomes 2/3 .What is the fraction?
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Given,
A fraction becomes 8/9 if 1 is added to both numerator and denominator.
And,when 5 is subtracted from numerator&denominator the fraction becomes 2/3 .
To find,
The actual fraction.
Solution,
Let,the numerator of the fraction = x
And,the denominator of the fraction = y
[Assume, x and y as variables to do the further mathematical calculations.]
So,the fraction = numerator/denominator = x/y
According to the question,
(x+1)/(y+1) = 8/9
9x+9 = 8y+8
9x = 8y-1
x = (8y-1)/9 .......(1)
And,
(x-5)/(y-5) = 2/3
3x-15 = 2y-10
3x = 2y+5
x = (2y+5)/3 ......(2)
By, comparing (1) and (2),we get that,
(8y-1)/9 = (2y+5)/3
24y-3= 18y+45
6y = 48
y = 8
By putting the value of y in (1),
x = (8×8-1)/9
x = (64-1)/9
x = 63/9
x = 7
Hence,the actual fraction is 7/8.
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