Math, asked by feroz, 1 year ago

at a party colas squash and fruit juice were offered to guests.one,fourth of the guests drank colas one third drank squash two fifth fruit juice and just three did not drink anything .how many guests were in all?

Answers

Answered by ARoy
188
Let the total no. of guests is x. Then x/4 guests drunk cola, x/3 guests drunk squash and 2x/5 guests drunk fruit juice.
Then by the given question, x-(x/4+x/3+2x/5)=3
or, x-(15x+20x+24x)/60=3
or, x-59x/60=3
or, (60x-59x)/60=3
or, x/60=3
or, x=60×3
or, x=180
Answered by windyyork
81

Answer: There were 180 guests in all.

Step-by-step explanation:

Since we have given that

Number of guests who did not drink anything = 3

Let the total number of guests be 'x'.

Number of guests drank colas = \dfrac{1x}{4}

Number of guests who drank squash = \dfrac{1x}{3}

Number of guests who drank fruit juice = \dfrac{2}{5}x

According to question, we get that

x-(\dfrac{x}{4}+\dfrac{x}{3}+\dfrac{2x}{5})=3\\\\x-\dfrac{15x+20x+24x}{60}=3\\\\x-\dfrac{59x}{60}=3\\\\\dfrac{60x-59x}{60}=3\\\\\dfrac{x}{60}=3\\\\x=60\times 3\\\\x=180

Hence, there were 180 guests in all.

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