A fraction in reduced form is such that when it is squared and then its numerator is reduced by 33(1/3)% and denominator is reduced to 20%, its result is twice the original fraction. The sum of numerator and denominator is:
A.8
B.13
C.17
D.15
Answers
Answered by
1
ĀNSWĒR ⏬⏬
A.8
Let the fraction be x/y.
When fraction is squared its numerator is reduced by 33(1/3) and denominator is reduced by 20%.
According to question,
(x/y)2 * 33(1/3)%/20% = 2(x/y).
Or, (x/y)2 * (2/3)/(1/5) = 2(x/y).
Or, x/y = 3/5. Sum of numerator and denominator is,
(x+y) = 3+5
= 8.
THANKS ✌✌
A.8
Let the fraction be x/y.
When fraction is squared its numerator is reduced by 33(1/3) and denominator is reduced by 20%.
According to question,
(x/y)2 * 33(1/3)%/20% = 2(x/y).
Or, (x/y)2 * (2/3)/(1/5) = 2(x/y).
Or, x/y = 3/5. Sum of numerator and denominator is,
(x+y) = 3+5
= 8.
THANKS ✌✌
Answered by
0
A fraction in reduced form is such that when it is squared and then its numerator is reduced by 33(1/3)% and denominator is reduced to 20%, its result is twice the original fraction. The sum of numerator and denominator is:
A.8
B.13
C.17
D.15
ĀNSWĒR ⏬⏬
A.8
THANKS ❤
#Nishu HarYanvi ♥
A.8
B.13
C.17
D.15
ĀNSWĒR ⏬⏬
A.8
THANKS ❤
#Nishu HarYanvi ♥
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