Question

A frame is formed by the uniform rods having a constant linear mass density. ACB part of frame is semicircular of radius R and AB is straight rod. Centre of mass of the system from centre O of AB is at a distance

Answer 1

Answer:2R/(π+2)

Explanation:

M1=xπR. (as cemtre of mass of the semi circular frame is on 2R/π)

M2=2xR

R1= 2R/π ( centre if nass of frame) and R2= 0 (on the axis)

Using formula (M1*R1+ M2*R2)/ M1+M2 AND PUTTING THE ABOVE GIVEN values the answer will cime out to be 2R/(π+2)