Question

A freely falling body acquires a velocity'v' m/s in falling through a distance of 80 m. How much further distance should it fall, so as to acquire a velocity of '2v' m/s

Answer 1

The acceleration is g for a freely falling body.

Here,

initial velocity,u=0

distance=h.

We use the formula,

v^2-u^2=2gh………….(1) Then,

v=(2gh)^1/2…………….(2)

When body moves further distance h, the total distance is 2h. Therefore,

v’=(4gh)^1/2=(2)^1/2v

Answer 2

Answer:

ANSWER

v

2

=2gs

v=

2gs

s=80,V=v

V=

2×10×80

=

1600

=40m/s

2V=

2gS

′

24×1600=2×10×S

′

S

′

=320m

Further distance =320−40=280m

Explanation:

hope it will help you

mark me as brainliest.....

And do follow me