Question

A freely falling body falling from a tower of hieght h covers a distance of h/2 in the last second of its motion.The hieght of the tower is nearly ?

(a)50m. (b)68 (c)45 (d)58

Answer 1

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A body freely falling from a tower covers a distance of S=h/2 in the last second of it's motion.the height of tower is?

6 years ago

Answers : (3)

is the ans 10

6 years ago

we have the formula - S = U + a/2(2N-1) [ WHERE U = INITIAL SPEED , & N = value of TIME IN Tth SECOND . ]

so using the formula ------

h/2 = u + a/2(2t-1)

h/10 = 2t-1 { u=0 & a=10}

t = h+10/20

so, total time = h+10/20

now by formula = h=ut + 1/2at^2, (u=0 a=10)

h=h^2+100+20h/80

on solving - h = 58.28 metres.

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