Question

a freely falling body reaches the ground in t seconds. The average velocity during its fall is:
a) gt/2 b) gt c) 2gt d) gt^2


Please answer me fast ​

Answer 1

We know that second equation of motion is given by

We know that second equation of motion is given byS=ut+

We know that second equation of motion is given byS=ut+ 2

We know that second equation of motion is given byS=ut+ 21

We know that second equation of motion is given byS=ut+ 21

We know that second equation of motion is given byS=ut+ 21 gt

We know that second equation of motion is given byS=ut+ 21 gt 2

We know that second equation of motion is given byS=ut+ 21 gt 2

We know that second equation of motion is given byS=ut+ 21 gt 2 where S = distance, u = initial velocity = 0 , t = time , g = acc. due to gravity

We know that second equation of motion is given byS=ut+ 21 gt 2 where S = distance, u = initial velocity = 0 , t = time , g = acc. due to gravity⇒S=

We know that second equation of motion is given byS=ut+ 21 gt 2 where S = distance, u = initial velocity = 0 , t = time , g = acc. due to gravity⇒S= 2

We know that second equation of motion is given byS=ut+ 21 gt 2 where S = distance, u = initial velocity = 0 , t = time , g = acc. due to gravity⇒S= 21

We know that second equation of motion is given byS=ut+ 21 gt 2 where S = distance, u = initial velocity = 0 , t = time , g = acc. due to gravity⇒S= 21

We know that second equation of motion is given byS=ut+ 21 gt 2 where S = distance, u = initial velocity = 0 , t = time , g = acc. due to gravity⇒S= 21 gt

We know that second equation of motion is given byS=ut+ 21 gt 2 where S = distance, u = initial velocity = 0 , t = time , g = acc. due to gravity⇒S= 21 gt 2

We know that second equation of motion is given byS=ut+ 21 gt 2 where S = distance, u = initial velocity = 0 , t = time , g = acc. due to gravity⇒S= 21 gt 2

We know that second equation of motion is given byS=ut+ 21 gt 2 where S = distance, u = initial velocity = 0 , t = time , g = acc. due to gravity⇒S= 21 gt 2 Since, u=0

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Answer 2

Answer:

Given:

u = 0

time = t secs

a = g

Using Newton's Second equation of motion,

s = ut + 1/2 at^2

= 0(t) + 1/2gt^2

s = gt^2/2

Avg. velocity = total displacement/

total time

<v> = gt^2/ 2t

<v> = gt/2

Hence, option (a) gt/2 is correct.

Hope it helps!