A freely falling body takes 2 s to reach the ground on a plane, when it is dropped from a height of 8 m. If the period of a simple pendulum is t seconds on the planet, calculate the length of the pendulum.
Answers
Answered by
8
Hii dear,
◆ Answer- l = t^2/9.87 m
◆ Explanation-
# Given-
h = 8 m
t' = 2 s
# Solution-
By Newton 2nd kinematic eqn,
s = ut' + 1/2 at'^2
8 = 0×2 + 1/2 × a × 2^2
a = 4 m/s^2
Period of pendulum is given by
t = 2π √(l/a)
l = t^2 × a / 4π^2
l = t^2 × 4 / 4π^2
l = t^2/9.87 m
Hope that is helpful...
◆ Answer- l = t^2/9.87 m
◆ Explanation-
# Given-
h = 8 m
t' = 2 s
# Solution-
By Newton 2nd kinematic eqn,
s = ut' + 1/2 at'^2
8 = 0×2 + 1/2 × a × 2^2
a = 4 m/s^2
Period of pendulum is given by
t = 2π √(l/a)
l = t^2 × a / 4π^2
l = t^2 × 4 / 4π^2
l = t^2/9.87 m
Hope that is helpful...
Similar questions