Question

- A freely falling body takes 8s to reach the ground. One second
after release, the percentage of its potential energy that is still
retained is​

Answer 1

Answer:

98.4 %

Explanation:

v = gt = 8x10 = 80m/s

H = v²/2g = 80²/20 = 320m.

the height H of the body before falling =  320m.

one second after release H2 = 320 - 1/2 gt² = 320 - 5 = 315

percentage of its potential energy  = 315/320 x 100% =  98.4 %