Question

A freely falling body travels which percent of distance in 3rd sec

Answer 1

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HERE IS UR ANSWER
s=1^2g (2t_1)
s=0.5×10 (2×3_1)
s=5 (5)
s=25m
HOPE IT HELPS U
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Answer 2

heya !! ☺
⭐ Given...
U = 0 , T = 3 s
S = ut + 1/2 gt ^2
S = 0*3+1/2*9.8 * 3^2
S = 44.1 .....
I hope it help's u...✌✌