Question

A frictionless string is placed on a pulley such that a mass of 6 kg placed at one end & a mass of 10kg placed at other end..find the tension in the string.?

Answer 1

Given:
m₁ = 6 kg, m₂ = 10kg

Formula Used:
$Tension = \frac{2g (m₁) (m₂)}{(m₁+m₂)}$
Now put the values,
We get,
$Tension = \frac{2*9.8*6*10}{6+10}$

Tension = $\frac{2*9.8*60}{16}$

Tension = 73.5 Newton

Answer 2

let g = acceleration due to gravity. Let the string and two masses move with
acceleration a. 10 kg moves down and 6kg moves up.

On the side of 10kg mass,     10 g - T = 10 a.    
On the side of 6 kg mass:         T - 6 g = 6 a

Add the equations to get    16 a = 4 g
a = 2.45 m/sec2.    So T = 6 ( g +a) = 73.5 Newtons.