A frictionless track ABCDE ends in a circular loop
of radius R. A body slides down the track from
point A which is at a height h= 5 cm. Maximum
value of R for the body to successfully complete
the loop is :-
(1) 5 cm.
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Answer:
For the body to complete the loop, the velocity at the bottom must be √5gR.
Now, So, by Work energy theorem
mgh = 1/2mv^2 = 1/2 m (5gR)
2gh = 5gR
R = 2/5*h = 2/5*5 cm = 2 cm
So, the maximum value of R = 2 cm.
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