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In figure, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm., find the area of the shaded region.
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ACB is a quadrant, subtend at 90° angle at
O
So, ø = 90° , r = 3.5cm
now,
Area of quadrant OACB
And, Area of ΔOBD
Area of the shaded region = Area of quadrant OACB − Area of ΔOBD
HENCE, Area of shaded region = 6.125cm²
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Anonymous:
where r u frm adhityashasan?
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Hence area of shaded region = area of quadrant - area of triangle
= 9.625-2.625
=7 answer
= 9.625-2.625
=7 answer
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