Question

A friend is spotted by lallo at a distance of 200m when lallo start to approach him the friends also stars moving in the same direction as lallo if the speed of his friend is 15kmph and that of lallo is 20 kpmh then how far will the friend have to walk before lalloo meets him

Answer 1

if i m not wrong distance travelled by his friend is 400/7 mt.

Answer 2

Answer:

85.69 m

Step-by-step explanation:

Total distance between friends = 200 m

Speed of lallo= 20 km/hr = $20 \times \frac{5}{18}=5.56 m/s$

Speed of friend= 15 km/hr = $15\times \frac{5}{18}=4.17 m/s$

Time = $\frac{Distance}{speed}$

Since they are moving in the opposite direction So, speeds will be added

So, Time = $\frac{200}{5.56+4.17}$

Time = $20.55$

Friend's distance in 20.55 seconds =$Speed \times time = 4.17 \times 20.55 =85.69$

So, The friend have to walk 85.69 m before lalloo meets him.