Question

A frog falls into a well that is 18
ft deep. Every day the frog jumps
up a total distance of 6 ft. At night,
as the frog grips the slimy well
walls, it slips back down by 2 ft.
At this rate, how many days will it
take the frog to jump to the rim of
the well?​

Answer 1

Answer: 4.5 days

Step-by-step explanation:

Frog falls into a well 18ft deep.

During the day the frog jumps up 6ft. At night drops 2ft.

So total distance in 1 day = 4ft

Therefore 18/4 = 4.5

Hope this helps!

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Answer 2

3 days 8hours

One day = 24 hrs:-(24÷3)

=8 hrs

the frog jump in one day=6 ft

he gone deep= 18+2

=20

solution-

18÷6=3

3 days

8 hrs

the required is 3 days 8 hrs