A frog falls into a well that is 18
ft deep. Every day the frog jumps
up a total distance of 6 ft. At night,
as the frog grips the slimy well
walls, it slips back down by 2 ft.
At this rate, how many days will it
take the frog to jump to the rim of
the well?
Answers
Answered by
0
Answer: 4.5 days
Step-by-step explanation:
Frog falls into a well 18ft deep.
During the day the frog jumps up 6ft. At night drops 2ft.
So total distance in 1 day = 4ft
Therefore 18/4 = 4.5
Hope this helps!
MARK AS BRAINLIEST!!
Answered by
0
3 days 8hours
One day = 24 hrs:-(24÷3)
=8 hrs
the frog jump in one day=6 ft
he gone deep= 18+2
=20
solution-
18÷6=3
3 days
8 hrs
the required is 3 days 8 hrs
Similar questions