Question

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Answer 1

Question :

Two numbers p and q are in the ratio of 3/5 : 4/3 respectively. By what percent is q more than p ?

Solution :

Ratio of p and q = 3/5 : 4/3 = 9 : 20 [ Multiplying by 15 ]

Let the two no. p and q be 9x and 20 respectively

Difference between q and p = 20x - 9x = 11x

Percentage that the q is more than p = ( Difference / No. p ) × 100

= ( 11x / 9x ) × 100

= ( 11 / 9 ) × 100

= ( 11 / 9 ) × 100

= 1100 / 9

= 122 2/9

Therefore q is 122 2/9 or 122.22 % more than p.

Answer 2

$\tt{\huge{\green{Solution _{NbT.YT }}}}$Question : ${\bold{100\:Points}}[\tex]\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ [tex]\huge{\fbox{\fbox{\orange{\mathfrak{Explanation\:Required}}}}}$$&lt; body bgcolor="black"&gt;&lt;font color="purple"&gt;$:arrow_right:Please answer, if you if felt this easy then definitely :ballot_box_with_check: check out my profile and kindly answer my questionsSolution : $\tt{\orange {Step-By-Step-Explaination \::- }}$From the question we can state that two numbers p and q are in the ratio 3/5 : 4/3 respectively.Ratio of p and q =&gt; 3/5 : 4/3 = &gt; 9 : 20Suppose there exists two numbers p and q which are equal to 9a and 20a respectively.Hence we find the difference between q and p to be equal to 11a∆q_{Grtr/P} =&gt; ( ∆ / P ) × 100 %= ( 11a / 9a ) × 100 %$= 122 \times \frac{2}{9} \%$: