Question

A frog hops 10 m along a straight-line path from point A to point B in 10 seconds and then turns around and hops 5 m till point C in another 5 seconds. The average speed and average velocity of frog will be

Answer 1

Answer:

AB= 9 units, BC = 5 units, AC = 4 units Average speed = Total distance/Total time Average velocity = Total displacement/ Total Time (a)A to B Average speed = 9/10 = 0.9 (here 7 to 0 is 7 units.0 to -2 is 2 units) as Displacement = Distance(in this case) Average velocity = Average speed = 0.9units (b) B to C Average speed=(9+5)/(10+5)=14/15units average velocity = 4/15units (note that displacement is the measure from initial to final point here he starts at 7 and finally reaches 3, i.e. 7-3=4)