Question

A fruit seller buy orange at the rate of 12 for 20 for hwo much should one orange o gain 25%

Answer 1

Answer:

Answer: Fruits are sold for a marginal LOSS of 2.7777

Method 1:

4 Fruits are bought for Rs 10

Each Fruit costs Rs (10/4) = Rs 2.5 Ps

5 Fruits are bought for Rs 10

Each Fruit costs Rs (10/5) = Rs 2.00 Ps

Average buying cost of each fruit is Rs [ ( 2.5 + 2.0)/2] = Rs (4.5/2) = Rs 2.25 Ps

As all 2 X number of fruits sold 9 numbers per Rs 20 each fruit sold at the cost of Rs (20/9)= Rs 2.22222

Hence Loss per a single fruit is Rs (2.25 - 2.22) = Rs 0.0277777 Ps or

an amount of Rs 2.7777 is loss for a transaction of 100 fruits

or Loss is 2.7777 %

Method 2:

If he bought equal number ‘X’ of each two types means he spent an amount to purchase 2 X number fruits at Rs [(10 X/4 ) + (10 X / 5)]= Rs (90 X/20)= Rs 4.5 X

Average cost of each fruit is Rs ( 4.5 X/2 X) = Rs 2.25 Ps

As all 2 X number of fruits sold 9 numbers per Rs 20 each fruit sold at the cost of Rs (20/9)= Rs 2.22222

Hence Loss per a single fruit is Rs (2.25 - 2.22222) = Rs 0.02777 Ps or

an amount of Rs 2.7777 is loss for a transaction of 100 fruits

or Loss is 2.7777 %

Verification:

For ease of calculations it is assumed 180 numbers of each type are purchased

First type fruits cost is (180/4) x Rs 10 = 45 x Rs 10 = Rs 450

Second type fruits cost is (180/5) x Rs 10 = 36 x Rs 10 = Rs 360

Total buying cost of 360 Fruits is Rs (450 + 360) = Rs 810

Selling price of 360 fruits at the rate of 9 per Rs 20 equal to (360/9) x Rs 20 or 40 x Rs 20 = 800

Hence the loss is Rs (810 - 800) = Rs 10

Or Percent of Loss a transaction of Rs 360 is [(10/360) x 100] = (0.0277777) x 100 = 2.7777