Question

A fruit seller had some oranges. He sells 30% oranges and still has 140 mangoes. Originally, he had:

A. 288 oranges

B. 300 oranges

C. 672 oranges

D. 200 oranges

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Answer 1

• Let number of oranges be M.

_______ [ ASSUME ]

A fruit seller sells 30% oranges and still has 140 oranges

________________ [ GIVEN ]

• We have to find the number of oranges.

______________________________

Fruit seller 30% of oranges.

So,

=> (100 - 30) = 70

He sell 70 oranges.

Now..

=> 70% of oranges = 140

=> 70/100 × M = 140

=> 70M/100 = 140

=> 70M = 140 × 100

=> 70M = 14000

=> M = 14000/70

=> M = 200

_____________________________

Total number of oranges he had = 200 oranges.

___________ [ ANSWER]

____________________________

☆ VERIFICATION :

From above calculations we have M = 200

Put value of M in this : 70/100 ×M = 140

=> 70/100× 200 = 140

=> 7/10 × 200 = 140

=> 1400/10 = 140

=> 140 = 140

____________________________

Answer 2

Answer:

Given,

sold = 30% of total oranges

remained with him= 140

Explanation:

let the total number of oranges be x

30% of x + 140 = x

$\frac{30}{100} \times x + 140 = x \\ = \frac{3x}{10} + 140 = x$

$\\ x - \frac{3x}{10} = 140 \\ \frac{10x - 3x}{10} = 140$

$\frac{7x}{10} = 140 \\ x = 200$