Question

In how many years rupees 1800 amount to 2178 at thee rate of 10% per annum

Answer 1

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Answer 2

$\bf{Given}$ :

Principal (P) = Rs. 1800
Rate of interest (R) = 10% per annum
Time (n) = ?
Amount (A) = Rs. 2178

$\mathbb{TO \: \: BE \: \: FOUND}$
Time (n)

$\bf{\underline {SOLUTION }}$

$Amount = P {(1 + \frac{R}{100}) }^{n} \\ \\ 2178=1800 {(1 + \frac{10}{100}) }^{n} \\ \\ 2178=1800 {(1 + \frac{1}{10}) }^{n} \\ \\ 2178=1800 {( \frac{10 + 1}{10}) }^{n} \\ \\ 2178=1800 {(\frac{11}{10}) }^{n} \\ \\ \frac{2178}{1800} = { (\frac{11}{10} )}^{n} \\ \\ \frac{121}{100} = { (\frac{11}{10} )}^{n} \\ \\ { (\frac{11}{10} )}^{2} = { (\frac{11}{10} )}^{n} \\ \\ now \: bases \: are \: same \\ now \: equating \: their \: powers \\ \\ 2 = n$

Hence, Time (n) = 2years.