Math, asked by narendramodi1754, 1 year ago

prove that there are infinitely many primes of the form 4k+3

Answers

Answered by AditiHegde
15

prove that there are infinitely many primes of the form 4k+3

  • Proof By Contradiction
  • Assumption: Assume we have a set of finitely many primes of the  form 4k+3
  • P = {p1, p2, …,pk}.
  • Construct a number N such that
  • N = 4 * p1* p2* … *pk – 1
  • = 4 [ (p1* p2* … *pk) – 1 ] + 3
  • N can either be prime or composite.
  • If N is prime, there’s a contradiction since N is in the form of 4k +3 but does not equal to any of the number in the set P.
  • If N is a composite, there must exist a prime factor “a” of N such  that a is in the form of 4k+3.
  • All the primes are either in the form of 4k+1 or in  the form of 4k+3. If all the prime factors are in the  form of 4k+1, N should also be in the form of 4k +1. There should exist at least one prime factor of  N in the form of 4k+3.
  • “a” does not belong to set P
  • N/a = (4 * p1* p2* … *pk – 1) / a
  • = (4 * p1* p2* … *pk ) / a - 1/a (1/a is not  an integer)
  • Conclusion:
  • a is a prime in the form of 4k+3, but a does not belong to set P.
  • Therefore, we proved by contradiction that there exists infinitely  many primes of the form 4k+3.
Answered by sunitasrivastava0101
1

Answer:

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