Math, asked by devilken7203, 1 year ago

A fruit seller had some oranges. he sells 40% oranges and still has 420 oranges. how many oranges he had originally

Answers

Answered by MridulAhi1234
39
Let the number of oranges be x.
He sold = 40% of x
Left = 100-40 = 60% of x
60/100x=420
3/5x=420
x= 420×5/3
x= 700
He had 700 oranges.

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Answered by pulakmath007
1

The fruit seller had 700 oranges originally

Given :

  • A fruit seller had some oranges.

  • He sells 40% oranges and still has 420 oranges

To find :

The number of oranges the fruit seller had originally

Solution :

Step 1 of 2 :

Form the equation to calculate the number of oranges the fruit seller had originally

Let number of oranges the fruit seller had originally = 100x

Since the fruit seller sells 40% oranges

∴ Number of oranges the fruit seller sells

= 40x

∴ Number of oranges left

= 100x - 40x

= 60x

By the given condition

\displaystyle \sf  60x = 420

Step 2 of 2 :

Calculate the number of oranges the fruit seller had originally

\displaystyle \sf  60x = 420

\displaystyle \sf{ \implies }x =  \frac{420}{60}

\displaystyle \sf{ \implies }x = 7

Hence number of oranges the fruit seller had originally

= 100x

= 100 × 7

= 700

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