Math, asked by whyyouwanttoknow, 17 days ago

A fruit seller losses 10% by selling 26 oranges for 25 rupees. what is the no. of oranges he should for 5 rupees to gain 17%​

Answers

Answered by Mysteryboy01
1

S.p  \: of  \: 1 \:  Orange = rs \frac{25}{26}

Loss  \: on  \: 26  \: Oranges \% = 10\%

 \frac{C.P - S.P}{C.P }  \times 100 = 10

 \frac{C.P - 25}{C.P }  \times 100 = 10

C.P - 25 = 0.1C.P

C.P  \: of \: 26 \: oranges \:  =  \frac{250}{9}

C.P  \: of \: 1 \: orange \:  =rs \frac{250}{234} = rs \frac{125}{117}

require \: profit \:  :

 \frac{5 - C.P2 }{C.P2}  \times 100 = 17

5 - C.P2 = 0.17C.P2

1.17C.P2 = 5

C.P2 = rs \frac{5}{1.17}

C.P \: of \: 1 \: orange \:  : rs1 \frac{125}{117}

no. \: of \: oranges \:  :  \frac{ \frac{5}{1.17} }{ \frac{125}{117} }  = 4

The \:  Answer \:  is \:  4

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