Question

Tickets numbered 1 to 20 are mixed up and a ticket is drawn at random. What is the
probability that the ticket drawn has a number which is a multiple of 3 or 5?

Answer 1

Step-by-step explanation:

no of possible outcomes=20

no of favourable outcomes=6

probability that the ticket drawn has a number multiple of 3 P(E)=6÷20

=3÷10

so probability is 3/10.

again

no of possible outcomes=20

no of favourable outcomes=4

probability that the ticket drawn has a number multiple of 5 P(E)=4÷20

=1/5

so probability is 1/5.