Question

a fruit vendor buys orange a fruit vendor buys oranges at 6 for Rs 10 and an equal number at 10 for Rs 20 he mixes them and sell at rupees 21.60 per dozen find the gain or loss percent

Answer 1

Its loss
as. 11x/3 > 3.6x or say
Clarification:
11/3 & 3.6
11/3 , 36/10

LCM 3 & 10 = 30

11 x 10 , 36 x 3
=110 > 108

Answer 2

Required Answer :

Given,

• A fruit vendor has to purchase equal number of oranges.

• Selling price per dozen = ₹21.60

• So he have purchased 6 oranges, Each from two cases.

Case (i) :

Cost of 6 orange = ₹10

Case (ii) :

Cost of 10 oranges = ₹20

_________________________

Cost of 6 oranges are given by,

$\dfrac{20}{10}$ × 6

= ₹12.

_________________________

So Total cost of 1 dozen Becomes,

10+12

= ₹ 22

_________________________

Now we can see that,

Cost price > Selling price

_________________________

We need to find the loss percentage;

Loss = Cost price - Selling price

Loss = 22 - 21.60

Loss = 0.40

_________________________

Now we need to find Loss percentage;

Loss % = $\dfrac{Lost}{Cost\;price}$ × 100

Loss % = $\dfrac{0.40}{22}$ × 100

Loss% = 1.81%