Question

A fruitseller bought certain number of mangoes. Later he found that 11% of the mangoes were spoilt. He sold 60% of the remaining mangoes and is still left with 534 mangoes. How many mangoes did he purchase initially?

Please tell the answer step by step..​

Answer 1

Answer:

He bought 500 Mangoes

Step-by-step explanation:

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Answer 2

Answer

First, we should find the number of mangoes left after spoiling.

Let the mangoes left after spoiling be x.

According to the question,

$\sf \dashrightarrow x - x \: of \: 60\% = 534$

$\sf \dashrightarrow x - x \times \dfrac{60}{100} = 534$

$\sf \dashrightarrow x - \dfrac{60x}{100} = 534$

$\sf \dashrightarrow\dfrac{100x - 60x}{100} = 534$

$\sf \dashrightarrow\dfrac{40x}{100} = 534$

$\sf \dashrightarrow 40x = 534 \times 100$

$\sf \dashrightarrow 40x = 53400$

$\sf \dashrightarrow x = \dfrac{53400}{40}$

$\sf \dashrightarrow x = 1335$

Now, we can find the number of mangoes he had totally.

Let the number of mangoes with fruit seller totally be y.

According to the question,

$\sf \dashrightarrow y - y \: of \: 11\% = 1335$

$\sf \dashrightarrow y - y \times \dfrac{11}{100} = 1335$

$\sf \dashrightarrow y - \dfrac{11y}{100} = 1335$

$\sf \dashrightarrow \dfrac{100y - 11y}{100} = 1335$

$\sf \dashrightarrow \dfrac{89y}{100} = 1335$

$\sf \dashrightarrow 89y = 1335 \times 100$

$\sf \dashrightarrow 89y = 133500$

$\sf \dashrightarrow y = \dfrac{133500}{89}$

$\sf \dashrightarrow y = 1500$

Hence, the fruit seller purchased 1500 mangoes initially.