Question

a frustum of cone has its radii of 15 cm and 7 cm height of 6 cm is completely filled with water find the volume of water and the curved surf
ace area of frustum of cone​ ? use π3.14

Answer 1

Answer:

i think answer is correct if any mistake is there comment me

Answer 2

The volume of the frustum of a cone can be calculated using the formula:

V = (π/3) × h × (r1^2 + r2^2 + r1 × r2),

where h is the height of the frustum, and r1 and r2 are the radii of the top and bottom circles, respectively. In this case, r1 = 15 cm, r2 = 7 cm, and h = 6 cm, so we have:

V = (π/3) × 6 × (15^2 + 7^2 + 15 × 7) = (π/3) × 6 × (225 + 49 + 105) = (π/3) × 6 × 379 = (π/3) × 2268 = 756π cm^3.

The curved surface area of a frustum of a cone can be calculated as follows:

A = π × (r1 + r2) × √((r1 - r2)^2 + h^2),

where r1 and r2 are the radii of the top and bottom circles, respectively, and h is the height of the frustum. In this case, r1 = 15 cm, r2 = 7 cm, and h = 6 cm, so we have:

A = π × (15 + 7) × √((15 - 7)^2 + 6^2) = π × 22 × √(64 + 36) = π × 22 × √100 = 22π × 10 = 220π cm^2.

So the volume of water in the frustum is 756π cm^3 and the curved surface area is 220π cm^2.

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