Math, asked by shwetapundir111197, 9 months ago

a fuel station sold diesel costing rs 15000 to 150 persons on a day if the lower limit of sale to a person is rs50 what is the maximum amount in rupees for which one person could have purchased diesel on that day

Answers

Answered by amitsnh
1

Answer:

the purchase by one person would be maximum if purchases by remaining 149 persons are minimum.

given,minimum purchase is of rs.50

purchase of 149 persons = 149*50 = 7450

maximum purchase by one person = remaining amount = 15000 - 7450

= 7550

Answered by swethassynergy
0

The value of   maximum amount for which one person could have purchased diesel on that day is Rs.7550.

Step-by-step explanation:

Given :

Total sold diesel costing is Rs.15000 .

Total persons is 150 .

The lower limit of sale to a person is Rs.50.

To Find :

The value of the maximum amount for which one person could have purchased diesel on that day.

Solution :

As given- total sold diesel costing is Rs.15000 .

To provide  maximum amount of purchased for one person , we have to provide  minimum purchased to rest of the members.

Therefore, Let one day except one Person ,diesel was  sold to  rest members to a amount equal to lower limit.

Then,  Number of   Members = 150 - 1 = 149 .

           Lower limit of sale to a person  = Rs.50 .

So,that day ,sold diesel costing to 149 members =149\times50= Rs. 7450

Total  sold diesel costing  per day is  Rs.15000.

Therefore, Sales of that particular person on that day

 = 15000 - 7450 = Rs.7550 .

Thus, the value of   maximum amount for which one person could have purchased diesel on that day is Rs.7550.

PROJECT CODE#SPJ3

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