A function f is defined as follows f(x) = 4x + 5, for -4 ≤ x < 0.
Find the values of f(-1), f(-2), f(0), if they exist.
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it is given that, a function f is defined as follow
f(x) = 4x + 5 , for -4 ≤ x < 0
we have to find f(-1) , f(-2) , f(0)
domain of given function, f belongs to [-4, 0)
means, function is defined at integral number , x = -4, -3, -2 , -1 .
function is undefined at x = 0 because 0 isn't included in domain of given function.
now, f(-1) = 4(-1) + 5 = -4 + 5 = 1
f(-2) = 4(-2) + 5 = -8 + 5 = -3
f(0) = doesn't exist.
f(x) = 4x + 5 , for -4 ≤ x < 0
we have to find f(-1) , f(-2) , f(0)
domain of given function, f belongs to [-4, 0)
means, function is defined at integral number , x = -4, -3, -2 , -1 .
function is undefined at x = 0 because 0 isn't included in domain of given function.
now, f(-1) = 4(-1) + 5 = -4 + 5 = 1
f(-2) = 4(-2) + 5 = -8 + 5 = -3
f(0) = doesn't exist.
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