A galvannometer has a resistance of 15ohm and the meter shows full deflection for a current of 4ma.how will you convert the galvannometer into ammeter of range 0 to 6a
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Resistance of the galvanometer coil G=15l
Ig=4×10−3A;I=6A
A small resistance which is called as shut resistance is connected in parallel , so that the galvanometer is covered into an ammeter.
S=Ig.GI−Ig
=4×10−3×156−4×10−3
=0.01Ω
Answer : 0.01Ω
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