Question

find value of (1+i)^6+(1-i) ^6

Answer 1

[tex] {{(1 + i)}^{2}}^3 + {{(1 - i)}^{2}}^3 \\ = ((1 + i)^2 +( 1 - i)^2)( {(1 + i)}^{4} + {(1 - i)}^{4} - (1 + i)^2(1 - i)^2)
=(2+2i^2)(4i^2+4i^2+4)
=(2-2)(-4-4+4)
=0