A galvanometer has a current 10microampere /divison and maximum voltage that can be applied is 100 V . Convert this galvanometer into an ammeter which can measure current 10mA /divison. Given total divisons = 10.
Answers
Answered by
0
Answer:
s =1
Explanation:
Since, 1 division measures 10 A and there are 100 such divisions, i = 1000 A
Using, the formula for the shunt resistance required,
S =i−igigG
S =1000−11×999
S = 1
Similar questions