Question

A galvanometer having a resistance of 8 ohm is shunted by a wire of resistance 2 ohm.If the total current is 1 a,the part of it passing through the shunt is

Answer 1

Here's your answer mate..

Answer 2

Answer:

Current of the shunt is 0.8 A

Step-by-step explanation:

Given,

Resistance of Galvanometer = 8 ohm

Resistance of Shunt = 2 ohm

Total Current = 1 A

Since we know,

$I_{s}=\frac{IG}{G+S}$

where,

$I_{s}$ is the shunt current

I is the total current

G is the Galvanometer resistance

S is the wire resistance

Substituting the values in the formula :

$I_{s}=\frac{1*8}{8+2}$

$I_{s}=\frac{8}{10}$

$I_{s}$ = 0.8 A

Hence,

Current of the shunt is 0.8 A