A galvanometer having resistance 20 and carrying current 40ma is converted into ammeter by 0.5 what resistance needed
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S/G = current through galvanometer/ current through shunt
so, S/G= 40 × 10^-3/0.5= 8 ×10^-2
S= 20 × 8× 10^-2= 1.6 ohm is the answer
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