Question

A galvanometer of resistance 20 ohm is to be converted into an ammeter of range 1a. Of a current of 1ma produces full scale deflection

Answer 1

Hii Dear,

◆ Answer -

Rs = 0.02 Ω

● Explanation -

# Given -

Ig = 1 mA = 0.001 A

Rg = 20 Ω

I = 1 A

# Solution -

Shunt resistance added to convert galvanometer to ammeter is calculated by -

Rs = Ig.Rg / (I-Ig)

Rs = 0.001 × 20 / (1 - 0.001)

Rs = 0.02 Ω

Therefore, a shunt resistance of 0.02 Ω need to be connected parallel to the galvanometer to convert it into ammeter.

Hope this is helpful...

Answer 2

$\Huge\underline{\underline{\sf Answer}}$

$\large\underline{\underline{\sf Resistance\:of\:shunt\:is\:0.02\:ohm}}$

$\Huge\underline{\underline{\sf Solution}}$

$\large\underline{\underline{\sf Given:}}$

• Galvanometer resistance (G) = 20ohm

• Current (i) = 1A

• Current through galvanometer $\sf{i_g}$= 0.01 A

$\large\underline{\underline{\sf To\:Find:}}$

• Shunt resistance (S) = ?

_______________________________________

We know ,

$\large{\boxed{\sf S=\frac{i_gG}{i-i_g}}}$

On Putting value

$\large\implies{\sf \frac{10^{-3}×20}{1-0.001}}$

$\large\implies{\sf \frac{0.02}{0.999}}$

$\large\implies{\sf 0.02\:ohm}$

Hence ,

$\large\underline{\underline{\sf Resistance\:of\:shunt\:is\:0.02\:ohm}}$