Question

A hammer being 3 kg moving with a velocity of 10 m/s strikes horizontally against the head of the nail driven it into block of wood if the hammer comes to rest in 0.025 sec find tge impluse and driving force of the nail

Answer 1

Answer:

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Answer 2

Explanation:

Here,

Mass m = 3 kg

Initial velocity u = 10 m/s

Final velocity v = 0 m/s

t = 0.025 s

Let a be the acceleration of the particle

We have,

v = u + at

=> a = (v-u)/t

=> a = (0-10)/0.025 = -400 ms-2

-ve sign shows the hammer is slowing down

Now force experienced by the hammer

F = ma = 3×400 = 1200 N

Now impulse I = F×t = 1200×0.025 = 30 Ns

Explanation:

We have F = Δp/t

I = F×t

=> I = (Δp/t)×t = Δp

Thus impulse is the change in momentum.

Force is the rate of change of momentum, now what affects the motion of a body is its change in momentum. Now small force acting for a large time will do the same action a large force that would do in a small time.

Take for example a large force of 40000 N acting for 0.0025 s will change the momentum of a body by 100 kg ms-1 again a small force of 1N acting for 100 s will change the momentum of a body by same 100 kg ms-1.

Thus, information on force is just not enough; we need to have more information about time the force acts on the body to get an idea of its motion. Impulse gives us the affect of force and the time it acts on the body. It gives us the change in momentum of the body.