A galvanometer resistance of 50 ohm gives full scale deflection with a current of 5 mA resistance of o.1M ohm is connected in series to convert it into vlot meter, find the range of voltmeter obtained .
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Solution,
The equt circuit diagram of
voltmeter will be
So,
15 = 5 x 10-³ (a+s) [onm's law]
⇒ 3000 = 50+ s
⇒ 2950 Ω = s
So, a 2950 resistor should
be combined in series with galvanometer to convert it in to voltmeter.
Hope it helps :)
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