Question

A game consists of tossing a coin 3 times and noting the outcome each time. If
getting the same result in all the tosses is a success, find the probability of
losing the game.​

Answer 1

Answer:

1/3 is correct answer as asked

Answer 2

Answer:

$\frac{3}{4}$

Step-by-step explanation:

If we toss a coin three times, the possible outcomes are

TTT, TTH, THT, THH, HTT, HTH, HHT, HHH

Now success is getting the same result in 3 tosses (TTT, HHH) i.e. 2 outcomes.

The outcomes where the game will be lost are (TTH, THT, THH, HTT, HTH, HHT) i.e. 6 outcomes.

As we know,

$probability = \frac{favourable \: outcomes}{total \: number \: of \: outcomes}$

So,probability of losing the game is:

$\frac{6}{8} = \frac{3}{4}$