Question

A game consists of tossing a one rupee coin 3 times and noting its outcome each time. Hanif wins if all the tosses give the same result i.e., three heads or three tails, and loses otherwise. Calculate the probability that Hanif will lose the game.

Answer 1

Hello!

Total number of outcomes = $\bf{8}$

$\underline{\sf Possible \:outcomes \:of \:3\: times\: tossing \:a\: coin}$ :

$\star \: \sf 1st = HHH \\ \\ \star\: \sf 2nd = HHT\: or \:HTH \:or\: THH \\ \\ \star \: \sf 3rd = TTH\: or \:THT\: or \:HTT \\ \\ \star \: \sf 4th = TTT$

Then,

P (Hanif losing the game) = $\dfrac{6}{8} = \boxed{\red{\bf{\dfrac{3}{4}}}}$

Cheers!

Answer 2

Answer:

Step-by-step explanation:

Probability of losing the game will be 3/4