Question

A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8, and these are equally likely outcomes. What is the probability that it will point at
(i) 8 ? (ii) an odd number?
(iii) a number greater than 2? (iv) a number less than 9?

Answer 1

both (1) and (4) are correct answer


(1) because we don't know 8 ke aghe Kia awe ga

and

4 is correct answer because

start from 1 and end is less than 9

that's why my answer is correct

Answer 2

Given:

• A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8, and these are equally likely outcomes.

To Find:

• The probability that it will point at 8.
• The probability that it will point at an odd number.
• The probability that it will point at a number greater than 2.
• The probability that it will point at a number less than 9.

Solution:

According to the question,

Given, Total number of possible outcomes = 8

$\implies P(E)=\frac{Number \: of \: favourable \: outcomes}{Total \:number \: of \: outcomes}$

Solution for your 1st question:

Total number of favourable events (i.e. 8) = 1

∴ P (pointing at 8) = $\frac{1}{8} = \boxed{\underline{\underline{0.125}}}$

Solution for your 2nd question:

Total number of odd numbers = 4 (1, 3, 5 and 7)

P (pointing at an odd number) = $\frac{4}{8} = \frac{1}{2} = \boxed{\underline{\underline{0.5}}}$

Solution for your 3rd question:

Total numbers greater than 2 = 6 (3, 4, 5, 6, 7 and 8)

P (pointing at a number greater than 4) = $\frac{6}{8} = \frac{3}{4} = \boxed{\underline{\underline{0.75}}}$

Solution for your 4th question:

Total numbers less than 9 = 8 (1, 2, 3, 4, 5, 6, 7, and 8)

P (pointing at a number less than 9) = $\frac{8}{8} = \boxed{\underline{\underline{0}}}$