A GAME CONSISTS OF TOSSING A ONE RUPPE COIN 3 TIMES AND AND NOTHING ITS OUTCOME EACH TIME. ARYAN WINS IF ALL TOSES GIVE THE SAME RESULT THAT IS THREE HEADS OR THREE TAILS AND LOSES OTHERWISE .THEN THE PROBABILITY THAT ARYAN WILL LOSE THE GAME
Answers
Q1. A dice is thrown. Find the probability of getting an even number.
(A) 2/3
(B) 1
(C) 5/6
(D) 1/2
Answer: (D)
Explanation: Total number of cases = 6 (1,2,3,4,5,6)
There are three even numbers 2,4,6
Therefore probability of getting an even number is:
P (even) = 3/6
⇒ P (even) = 1/2
Q2. Two coins are thrown at the same time. Find the probability of getting both heads.
(A) 3/4
(B) 1/4
(C) 1/2
(D) 0
Answer: (B)
Explanation: Since two coins are tossed, therefore totalnumber of cases = 22 = 4
Therefore, probability of getting heads in both coins is:
∴ P (head) = 1/4
CBSE Class 10th Maths Chapter-wise Important Formulas, Theorems & Properties
Q3. Two dice are thrown simultaneously. The probability of getting a sum of 9 is:
(A) 1/10
(B) 3/10
(C) 1/9
(D) 4/9
Answer: (C)
Explanation: Total cases = 36
Total cases in which sum of 9 can be obtained are:
(5, 4), (4, 5), (6, 3), (3, 6)
∴ P (9) = 4/36 = 1/9
Q4. 100 cards are numbered from 1 to 100. Find the probability of getting a prime number.
(A) 3/4
(B) 27/50
(C) 1/4
(D) 29/100
Answer: (C)
Explanation: Total prime numbers from 1 to 100 are:
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97
That means 25 out of 100
So probability is:
P (prime) = 25/100
⇒ P (prime) = 1/4
Q5. A bag contains 5 red balls and some blue balls .If the probability of drawing a blue ball is double that of a red ball, then the number of blue balls in a bag is:
(A) 5
(B) 10
(C) 15
(D) 20
Answer: (B)
Explanation: Let the number of blue balls be x
Then total number of balls will be 5 + x.
According to question,
x/(5 + x) = 2 X (5/5+x)
⇒ x = 10
hope u understand by some of these examples
The probability that Aryan loses the game is 3/4.
Given: The tossing of three coins. Aryan wins if all tosses give 3 heads or 3 tails otherwise he loses.
To Find: The probability that Aryan will lose the game
Solution:
When 3 coins are tossed simultaneously, the sample space we get is;
S = { HHH, HHT, HTH, THH, HTT, THT, TTH, TTT }
Now, Aryan will win if he gets all heads or all tails,
⇒ P ( Winning ) = { HHH, TTT }
= 2/8
= 1/4
∴ P ( Losing ) = 1 - P ( Winning ) [ using complement law ]
= 1 - 1/4
= 3/4
Hence, the probability that Aryan loses the game is 3/4.
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