Question

A game of chance consists of spinning an arrow which comes to rest pointing at one of the number 1,2,3,4,5,6,7,8 and these are equally likely outcomes. what is the probability that it will point at.

(1) 8 ?
(2) an odd number ?
(3) a number greater than 2 ?
(4) a number less than 9 ?​

Answer 1

$\sf\pink{refer}$ $\sf\orange{the}$ $\sf\green{given}$ $\sf\red{attachment}$

Answer 2

Step-by-step explanation:

$solution \\ \: \: \: \: \: \: the \: disc \: contains \: 8 \: numbers \\ s = (1 \: 2 \: 3 \: 4 \: 5 \: 6 \: 7 \: 8) \\ n(s) = 8 \\ (1)let \: a \: be \: the \: event \: that \: the \: arrow \\ comes \: to \: rest \: at \: 8 \\ \: \: \: then \: a \: = (8) \\ \: \: \: \: \: \: \: n(a) = 1 \\ \: \: \: p(a) = \frac{n(a)}{n(s)} = \frac{1}{8} \\ 2)let \: b \: be \: the \: event \: that \: the \: arrow \\ comes \: to \: rest \: at \: an \: odd \: number \\ then \: b = (1 \: 3 \: 5 \: 7) \\ \: \: \: \: n(b) = 4 \\ \: \: \: \: p(b) = \frac{n(b)}{n(s)} = \frac{4}{8} = \frac{1}{2} \\ 3)let \: c \: be \: the \: event \: that \: the \: arrow \: \\ comes \: to \: rest \: at \: a \: number \: greater \: \\ than \: 2. \\ then \: c \: = (3 \: 4 \: 5 \: 6 \: 7 \: 8) \\ \: \: \: \: \: n(c) = 6 \\ \: \: \: \: \: p(c) = \frac{n(c)}{n(s)} = \frac{6}{8} = \frac{3}{4} \\ 4)let \: d \: be \: the \: event \: that \: the \: arrow \\ comes \:at \: a \: number \: less\: than \: 9 \\ then \: d \: (1 \: 2 \: 3 \: 4 \: 5 \: 6 \: 7 \: 8) \\ \: \: \: \: \: n(d) = 8 \\ p(d) = \frac{n(d)}{n(s)} = \frac{8}{8} = 1 \\ \\ \\ (1) \frac{1}{8} \: \: \: (2) \frac{1}{2} \: \: \: (3) \frac{3}{4} \: \: \: (4)1$

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