a garden 18m by 15 m is surrounded by a path of uniform width 2.25.find the area of the path .
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Answer:
168.75 m²
Step-by-step explanation:
Observe the attached figure. PQRS is the garden and ABCD is the outer edges of the Path.
In rectangle ABCD
AB = CD = 18m + 2.25m + 2.25m
= 22.5 m
and BC = CD = 15m + 2.25m + 2.25m
= 19.5m
Now, Area of path will be
Area of ABCD - Area of PQRS
= (22.5 × 19.5) - (18 × 15) [Area of Rectangle = Length × Breadth]
= 168.75 m²
Hence, Area of Path will be 168.75 m²
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