Question

a garden is in the shape of a trapezium. its parallel sides are of lengths 20m and 16m and distance between the parallel sides is 12 m.find the area of the garden

Answer 1

$length \: of \: parallel \: side \: (a) = 20m \\ \\ b = 16m \\ \\ area \: of \: garden = area \: of \: trapezium \\ \\ area \: of \: garden \: = \frac{1}{2} \times h(a + b) \\ \\ \: \: \: \: \: \: \: \: = \frac{1}{2} \times 12(20 + 16) \\ \\ \: \: \: \: \: = \frac{1}{2} \times 12 \times 36 \\ \\ \\ = 216m {}^{2}$

Answer 2

Answer:

Step-by-step explanation:

First divide the trapezium into a triangle and a parallelogram.

The area of is half * base *height. So we have height 12 and base as 4( as opposite sides of parallelogram are equal) so the area becomes 24m square.

Now area of parallelogram is base*height.

So we have base 16m and height 12m .

Now we get the area as 192m square.

Now area of parallelogram + area of is equal to the area of trapezium.

Thus 192m square + 24m square= 216m square