Math, asked by sonianita49723, 10 months ago

A garden of length 430m and breadth 120m is planted leaving a border of 2m long the four sides Find the area of the portion which is not planted. Find the cost of planting the garden at the rate of Rs. 100 per sq.m

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Answers

Answered by BrainlyQueen01
13

Answer:

\boxed{\red{\bf{Cost\:of\:planting\:=\:Rs\:4,941,600}}}

\boxed{\red{\bf{Area\:of\:remaining\:portion=2,184\:m^2}}}

Step-by-step explanation:

Let the outer rectangle be ABCD and inner rectangle be abcd. [Refer to attachment]

Given that -

  • Length of outer rectangle = 430 m
  • Breadth of inner rectangle = 120 m

Area of outer rectangle = Length * Breadth

= (430 * 120) m²

= 51,600 m²

Now, consider inner rectangle abcd.

  • Length of inner rectangle = (430 - 4) = 426 m.
  • Breadth of inner rectangle = (120 - 4) = 116 m.

Area of inner rectangle = Length * Breadth

                                        = (426 * 116) m².

                                        = 49,416 m².

Area of portion which is not planted = Area of outer rectangle - Area of inner rectangle.

                              = (51,600 - 49,416) m²

                              = 2,184 m²

Coming to the next part -

Cost of planting 1 m² = Rs 100.

Cost of planting 49,416 m² = Rs (49,416 * 100)

                                              = Rs 4,941,600.

Therefore, the area of the portion which is not planted is 2,184 .

And, the cost of planting the garden is Rs 4,941,600.

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