Question

a gardener moves a lawn roller through a distance of 100m with the force of 50n calculate the work done if the applied force is inclined to 60 to the direction of motion ...formula and explanations please ​

Answer 1

Answer:-

Given:

Displacement (S) = 100 m

Force (F) = 50 N

Angle at which the force is inclined (θ) = 60°

We know that,

Work done (W) = FS cos θ

So,

⟶ W = (50)(100) cos 60°

• cos 60° = 1/2

⟶ W = 5000 × (1/2)

⟶ W = 2500 J

∴ The work done by the gardener is 2500 Joules.

Additional Information:-

• Work is simply defined as the product of force and displacement.

• Work is denoted by W

• W = FS (or) W = FS cos θ

• S I unit of work is Joules. C.G.S unit erg.

• 1 J = 10⁷ ergs

• work is a Scalar Quantity

Answer 2

Answer:

✯ Given :-

• A gardener moves a lawn roller through a distance of 100 m with the force of 50 N. The applied force is inclined to 60° to the direction of motion.

✯ To Find :-

• How much work done by the gardener.

✯ Formula Used :-

✪ Work Done = FS cos $\theta$ ✪

✯ Solution :-

⋆ Given :-

• Force (F) = 50 N
• Displacement (S) = 100 m
• Angle by which the force is inclined ($\theta$) = 60°
• We know that cos 60° = $\dfrac{1}{2}$

➣ According to the question by using the formula we get,

⇒W = 50 × 100 × cos 60°

⇒W = 5000 × $\dfrac{1}{2}$

➙ W = 2500 J

$\therefore$ The work done by the gardener is $\boxed{\bold{\large{2500\: J}}}$

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